#### Answer

The ratio of the sun's gravitational force on a person and the earth's gravitational force on a person is $6.02\times 10^{-4}$

#### Work Step by Step

Let $M_s$ be mass of the sun.
Let $R_s$ be the distance from a person to the sun.
Let $M_p$ be the mass of a person.
We can write an expression for the force of gravity $F_s$ of the sun on a person.
$F_s = \frac{G~M_s~M_p}{R_s^2}$
Let $M_e$ be the mass of the earth. Let $R_e$ be the earth's radius. We can write an expression for the force of gravity $F_e$ of the earth on a person.
$F_e = \frac{G~M_e~M_p}{R_e^2}$
We can find the ratio of $\frac{F_s}{F_e}$.
$\frac{F_s}{F_e} = \frac{(\frac{G~M_s~M_p}{R_s^2})}{(\frac{G~M_e~M_p}{R_e^2})}$
$\frac{F_s}{F_e} = \frac{M_s~R_e^2}{M_e~R_s^2}$
$\frac{F_s}{F_e} = \frac{(1.989\times 10^{30}~kg)(6.38\times 10^6~m)^2}{(5.98\times 10^{24}~kg)(1.50\times 10^{11}~m)^2}$
$\frac{F_s}{F_e} = 6.02\times 10^{-4}$
The ratio of the sun's gravitational force on a person and the earth's gravitational force on a person is $6.02\times 10^{-4}$.