Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 10 - Interactions and Potential Energy - Exercises and Problems - Page 255: 1

Answer

Velocities differ with varying masses and object so you must use p=mv and then compare.

Work Step by Step

p(1) = (20 g)(1 m/s) = 20 gm/s p(2) = (20 g)(2 m/s) = 40 gm/s p(3) = (10 g)(2 m/s) = 20 gm/s p(4) = (0 g)(1 m/s) = 10 gm/s p(5) = (200 g)(0.1 m/s) = 20 gm/s So, p(2) > p(1)=p(3)=p(5)>p(4)
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