Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 1 - Concepts of Motion - Exercises and Problems - Page 31: 55


$V = 2.4\times 10^{-4}~m^2$

Work Step by Step

The volume of a cylinder is $V = \pi r^2 h$ $V = \pi r^2 h = \pi (0.025~m)^2(0.12~m)$ $V = 2.4\times 10^{-4}~m^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.