Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 1 - Concepts of Motion - Exercises and Problems - Page 30: 35

Answer

The acceleration is 8.75 m/s^{2}

Work Step by Step

The initial speed of a plane is 300 m/s Distance covered by plane is 4 km or 4000 m The final speed of the plane is 400 m/s Use kinematical equation V(final)^{2} = V(initial)^{2} + 2ad Substitute known values (400 m/s)^{2} = (300 m/s)^{2} + 2a(4000 m) (400 m/s)^{2} - (300 m/s)^{2} = (8000m)a 7000 m/s^{2}/8000m = a Therefore, the acceleration of the plane is 8.75 m/s^{2}.
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