#### Answer

The coin will not slide off.

#### Work Step by Step

We can find the maximum possible force of static friction.
$F_f = mg~\mu_s$
$F_f = (0.0050~kg)(9.80~m/s^2)(0.80)$
$F_f = 0.0392~N$
We can find the speed of the coin as it rotates at a rate of 60 rpm.
$v = (60~rpm)(2\pi~r)(\frac{1~min}{60~s})$
$v = (60~rpm)(2\pi)(0.15~m)(\frac{1~min}{60~s})$
$v = 0.942~m/s$
We can find the centripetal force required to keep the coin moving around in a circle.
$F_c = m~\frac{v^2}{r}$
$F_c = (0.0050~kg)~\frac{(0.942~m/s)^2}{0.15~m}$
$F_c = 0.0296~N$
Since the maximum force of static friction on the coin is greater than the required force to keep the coin moving around in a circle, the coin will not slide off.