#### Answer

The velocity at t = 6 seconds is $4 ~m/s$

#### Work Step by Step

From the graph, we can see that the average force from 0 to 4 seconds is 5.0 N. We can use the average force to find the average acceleration from 0 to 4 seconds. Therefore:
$F_{ave} = ma_{ave}$
$a_{ave} = \frac{F_{ave}}{m}$
$a_{ave} = \frac{5.0~N}{5.0~kg}$
$a_{ave} = 1.0~m/s^2$
We can find the velocity at t = 4 seconds.
$v_f = v_0+a_{ave}~t$
$v_f = 0+(1.0~m/s^2)(4~s)$
$v_f = 4~m/s$
Since the force from t = 4 s to t = 6 s is zero, the acceleration is also zero. Therefore, the velocity at t = 6 s is equal to the velocity at t = 4 s.
The velocity at t = 6 seconds is $4 ~m/s$.