Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 6 - Dynamics I: Motion Along a Line - Exercises and Problems - Page 162: 16


(a) $F_T = 3.96~N$ (b) $F_T = 2.32~N$

Work Step by Step

Let $F_T$ be the rocket's thrust. Therefore; (a) $\sum F = ma$ $F_T - mg = ma$ $F_T = m(g+a)$ $F_T = (0.200~kg)(9.80~m/s^2+10~m/s^2)$ $F_T = 3.96~N$ (b) $\sum F = ma$ $F_T - mg_M = ma$ $F_T = m(g_M+a)$ $F_T = (0.200~kg)(1.62~m/s^2+10~m/s^2)$ $F_T = 2.32~N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.