## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

(a) $F_T = 3.96~N$ (b) $F_T = 2.32~N$
Let $F_T$ be the rocket's thrust. Therefore; (a) $\sum F = ma$ $F_T - mg = ma$ $F_T = m(g+a)$ $F_T = (0.200~kg)(9.80~m/s^2+10~m/s^2)$ $F_T = 3.96~N$ (b) $\sum F = ma$ $F_T - mg_M = ma$ $F_T = m(g_M+a)$ $F_T = (0.200~kg)(1.62~m/s^2+10~m/s^2)$ $F_T = 2.32~N$