Answer
a) $\vec a_x = -1\hat i m/s^2$
b) $ \vec a_y =0 m/s^2$
Work Step by Step
a) Net Force acting along the x-axis
$\vec F_x = 2.0N \hat i - 4.0N\hat i \\ \vec F_x = - 2.0N\hat i \\ \therefore \vec a_x = \frac{\vec F_x}{m} =\frac{ -2.0\hat i}{2.0} = -1\hat i m/s^2 $
b) Net Force acting along the y-axis
$\vec F_y = 3.0N \hat j - 3.0N\hat j \\ \vec F_y = 0N \\ \therefore \vec a_y = \frac{\vec F_y}{m} =\frac{ 0}{2.0} = 0 m/s^2 $
