Answer
$T_1 = 86.6~N$
$T_2 = 50.0~N$
Work Step by Step
The vertical component of $T_3$ is equal in magnitude to $T_2$. We can find the magnitude of $T_2$.
$T_2 = T_3~sin(\theta)$
$T_2 = (100~N)~sin(30^{\circ})$
$T_2 = 50.0~N$
The horizontal component of $T_3$ is equal in magnitude to $T_1$. We can find the magnitude of $T_1$.
$T_1 = T_3~cos(\theta)$
$T_1 = (100~N)~cos(30^{\circ})$
$T_1 = 86.6~N$
