Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 39 - Wave Functions and Uncertainty - Exercises and Problems - Page 1175: 8

Answer

${\bf 2\times 10^7}\;\rm photon$

Work Step by Step

We know that the probability density is given by $$\text{Prob}( \text{in } \delta x \text{ at } x)=P(x)\delta x=\dfrac{N }{N_{tot}}$$ where $N_{tot}$ is the total number of photons, and $N$ is the number of photons detected at position $\delta x$. Hence, $$N=N_{tot}P(x)\delta x$$ Plug the known; $$N=(1\times 10^{10}) (20)(0.1\times 10^{-3})$$ $$N =\color{red}{\bf 2\times 10^7}\;\rm photon$$
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