Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 39 - Wave Functions and Uncertainty - Exercises and Problems - Page 1175: 19

Answer

${\bf 25}\;\rm ns$

Work Step by Step

To determine the shortest duration radio-frequency pulse that can be amplified without distortion, we use $$ \Delta f \approx \dfrac{1}{\Delta t } \tag 1$$ where $ \Delta f $ is the bandwidth, and $ \Delta t$ is the shortest pulse duration. Noting that the bandwidth $ \Delta f$ is the difference between these two frequencies: $$ \Delta f = 120 - 80 = \bf 40 \; \rm{MHz} \tag 2$$ Solving (1) for $\Delta t$; $$\Delta t\approx\dfrac{1}{\Delta f}\tag 3$$ Plug into (2) into (3) to calculate the shortest pulse duration; $$ \Delta t = \frac{1}{40\times 10^6} =\color{red}{\bf 25}\;\rm ns$$ Thus, the shortest duration radio-frequency pulse that can be amplified without distortion is 25 ns.
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