Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 20 - Traveling Waves - Exercises and Problems: 2

Answer

If the tension is doubled, the speed is 283 m/s

Work Step by Step

We can write an expression for the initial speed which is 200 m/s: $v_1 = \sqrt{\frac{T_1}{\mu}}$ We can find the final speed as: $v_2 = \sqrt{\frac{T_2}{\mu}}$ $v_2 = \sqrt{\frac{2T_1}{\mu}}$ $v_2 = \sqrt{2}~\sqrt{\frac{T_1}{\mu}}$ $v_2 = \sqrt{2}~v_1$ $v_2 = \sqrt{2}~(200~m/s)$ $v_2 = 283~m/s$ If the tension is doubled, the speed is 283 m/s.
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