Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can write an expression for the initial speed which is 200 m/s: $v_1 = \sqrt{\frac{T_1}{\mu}}$ We can find the final speed as: $v_2 = \sqrt{\frac{T_2}{\mu}}$ $v_2 = \sqrt{\frac{2T_1}{\mu}}$ $v_2 = \sqrt{2}~\sqrt{\frac{T_1}{\mu}}$ $v_2 = \sqrt{2}~v_1$ $v_2 = \sqrt{2}~(200~m/s)$ $v_2 = 283~m/s$ If the tension is doubled, the speed is 283 m/s.