## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson

# Chapter 20 - Traveling Waves - Exercises and Problems: 14

#### Answer

The amplitude is 6 cm $f = 1.7~Hz$ $\lambda = 1.2~m$

#### Work Step by Step

The point x = 0 m oscillates between -6 cm and 6 cm. Therefore, the amplitude is 6 cm. The wave completes one oscillation in 0.6 seconds. Therefore, the period $T = 0.6~s$. We can find the frequency as: $f = \frac{1}{T}$ $f = \frac{1}{0.6~s}$ $f = 1.7~Hz$ We can find the wavelength as: $\lambda = \frac{v}{f}$ $\lambda = \frac{2.0~m/s}{1.7~Hz}$ $\lambda = 1.2~m$

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