#### Answer

(a) $x = \frac{5}{3}~m$
(b) v = 2 m/s
(c) $a = 4~m/s^2$

#### Work Step by Step

(a) $v(t) = 2t^2$
$x(t) = x_0+\int_{0}^{t}~v_x(t)~dt$
$x(t) = x_0+\int_{0}^{t}~2t^2~dt$
$x(t) = \frac{2}{3}t^3+1~m$
At t = 1 s:
$x = \frac{2}{3}(1~s)^3+1~m$
$x = \frac{5}{3}~m$
(b) $v(t) = 2t^2$
At t = 1 s:
$v = (2)(1~s)^2$
$v = 2~m/s$
(c) $a(t) = \frac{dv}{dt}$
$a(t) = 4t$
At t = 1 s:
$a = (4)(1~s)$
$a = 4~m/s^2$