Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 2 - Kinematics in One Dimension - Exercises and Problems: 23

Answer

(a) $x = 7~m$ (b) $v = 7~m/s$ (c) $a = 4~m/s^2$

Work Step by Step

(a) $x(t) = 2t^2 -t+1$ At t = 2 s: $x = (2)(2~s)^2-(2~s)+1$ $x = 7~m$ (b) $v(t) = \frac{dx}{dt} = 4t-1$ At t = 2 s: $v = (4)(2~s)-1$ $v = 7~m/s$ (c) $a(t) = \frac{dv}{dt} = 4$ At t = 2 s: $a = 4~m/s^2$
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