## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

The new temperature is $293^{\circ}C$
We can convert the initial temperature $t_1$ to Kelvin; $K = C+273$ $K = 10+273$ $K = 283$ Therefore; $t_1 = 283 ~K$ Let $t_2$ be the new temperature of the sample.; $t_2 = 2t_1$ $t_2 = (2)(283~K)$ $t_2 = 566~K$ We then convert the new temperature to degrees Celsius: $C = K - 273$ $C = 566 - 273$ $C = 293$ The new temperature is $293^{\circ}C$.