Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 16 - A Macroscopic Description of Matter - Conceptual Questions: 1

Answer

$T_2>T_3>T_1$

Work Step by Step

We can convert $T_1$ to degrees Celsius; $C = K - 273$ $C = 0 - 273$ $C = -273$ Therefore; $T_1 = -273^{\circ}C$ We can convert $T_3$ to degrees Celsius; $C = \frac{5}{9}(F-32)$ $C = \frac{5}{9}(0-32)$ $C = -18$ Therefore; $T_3 = -18^{\circ}C$ We can rank the three temperatures from highest to lowest: $ 0^{\circ}C> -18^{\circ}C> -273^{\circ}C$ $T_2>T_3>T_1$
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