## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$f = 3.5~Hz$
We can find an expression for $\frac{k}{m}$ as: $kx = mg$ $\frac{k}{m} = \frac{g}{x}$ We then find the frequency of oscillation; $f = \frac{1}{2\pi}~\sqrt{\frac{k}{m}}$ $f = \frac{1}{2\pi}~\sqrt{\frac{g}{x}}$ $f = \frac{1}{2\pi}~\sqrt{\frac{9.80~m/s^2}{0.020~m}}$ $f = 3.5~Hz$