Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 14 - Oscillations - Exercises and Problems: 12

Answer

$k = 5.48~N/m$

Work Step by Step

We first find the period as: $T = \frac{time}{cycles}$ $T = \frac{12.0~s}{10~oscillations}$ $T = 1.20~s$ We then find the spring constant as: $T = 2\pi~\sqrt{\frac{m}{k}}$ $k = \frac{(2\pi)^2~m}{T^2}$ $k = \frac{(2\pi)^2~(0.200~kg)}{(1.20~s)^2}$ $k = 5.48~N/m$
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