## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$k = 5.48~N/m$
We first find the period as: $T = \frac{time}{cycles}$ $T = \frac{12.0~s}{10~oscillations}$ $T = 1.20~s$ We then find the spring constant as: $T = 2\pi~\sqrt{\frac{m}{k}}$ $k = \frac{(2\pi)^2~m}{T^2}$ $k = \frac{(2\pi)^2~(0.200~kg)}{(1.20~s)^2}$ $k = 5.48~N/m$