## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can calculate the torque about an axis of rotation perpendicular to the left end of the rod. Note that the 40-N force exerts a torque of zero about this axis. $\tau = r_1\times F_1+r_2\times F_2$ $\tau = -(2.0~m)(100~N)+(3.0~m)(60~N)$ $\tau = -20~N~m$ Since the torque is non-zero, the object is not in equilibrium.