Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 11 - Work - Exercises and Problems - Page 307: 71

Answer

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Work Step by Step

The first given formula seems to be a net force exerted on an object vertically. The net force here is NOT zero which means that the object is accelerating upward at a constant rate. The second formula is the power output of the tension force when the object's speed is 2 m/s. a) An elevator of 1500 kg mass is pulled up by a wire that is attached to a frictionless pulley. It is accelerating upward at a constant rate of 1 $\rm m/s^2$. Find the tension on the wire, then find the power output of the motor when the speed of the elevator is 2 m/s. b) See the figure below. c) Solving the first formula for $T$; $$T=(1500\times 1)+(1500\times 9.8)=\color{red}{\bf 1.62\times 10^4}\;\rm N$$ Solving the second formula for $P$; $$P=Tv=1.62\times 10^4\times 2=\color{red}{\bf 3.24\times 10^4}\;\rm W$$
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