Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 11 - Work - Exercises and Problems - Page 307: 69

Answer

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Work Step by Step

The given formula seems to be a conservation of energy equation. The first term is kinetic energy while the second term seems to be thermal energy done by a friction force that has a coefficient of friction of 0.15 while the object is moving on a tilted surface at $40^\circ$. The last term is the initial gravitational energy. a) A box of mass 20 kg was initially at rest on a rough surface that has a coefficient of friction between it and the box of 0.15. This surface is tilted about 40$^\circ$ above the horizontal. It was initially at a height of 2.5 m and starts to slide down the incline from rest. Find its speed at the bottom of the tilted surface. b) See the figure below. c) Solving the given formula for $v_1$: We can see that the mass of the box is a common factor, so we can divide both sides by $ 2.5\;\rm kg$. We also need to multiply both sides by 2. $$v_1=\sqrt{\left[2\times9.8\times 2.5\right]-\left[ 2\times 0.15 \times 9.8\times 2.5\times \dfrac{\cos40^\circ}{\sin40^\circ}\right]}$$ $$v_1=\color{red}{\bf 6.3}\;\rm m/s$$
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