## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

The work that the cat does will be equal to the initial kinetic energy as the cat leaves the floor. The kinetic energy will be equal to the potential energy at maximum height. Therefore, the work done by the cat will be equal to the potential energy at maximum height. $W = PE$ $W = mgh$ $W = (5.0~kg)(9.80~m/s^2)(0.95~m)$ $W = 46.55~J$ We can find the cat's average power output. $P = \frac{Work}{time}$ $P = \frac{46.55~J}{0.20~s}$ $P = 9.3~watts$ The cat's average power output is 9.3 watts.