Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 1 - Concepts of Motion - Exercises and Problems - Page 30: 30

Answer

$\rm4\; m\approx 13 \;ft$

Work Step by Step

We can say that the length of a typical car is 4 meters. $\rm 4\;m=4\;\rm m\cdot \left(\dfrac{39.37\;in}{1\;m}\right)\cdot\left(\dfrac{1\;ft}{12\;in}\right) $ The units of $\rm m$ and $\rm in$ cancel and the unit of $\rm fr$ remains. Thus, $\boxed{\rm 4\;\rm m\approx 13.12\;\rm ft}$ We arrived to this estimate by assuming that the length of the car is double the width of the car and that the width of the car is 2 meters.
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