Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 1 - Concepts of Motion - Exercises and Problems - Page 30: 29


Please see the work below.

Work Step by Step

We know that (a) $(12.5)^3=1.95\times 10^3$ (b) $12.5\times 5.21=65.1$ (c) $\sqrt{12.5} -1.2=3.54-1.2=2.3$ (d) $(12.5)^{-1}=\frac{1.00}{12.5}=0.0800\times 10^{-2}$
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