Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Problems - Page 213: 22


a) $\theta=4600rad$ b) $\alpha=200rad/s^2$

Work Step by Step

The initial speed is $\omega_0=420rad/s$, the final speed is $\omega=1420rad/s$, and the time is $t=5s$ a) The angle through which the rotor turns is $$\theta=\Big(\frac{\omega+\omega_0}{2}\Big)t=4600rad$$ b) The magnitude of the angular acceleration is $$\alpha=\frac{\omega-\omega_0}{t}=200rad/s^2$$
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