Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Problems - Page 213: 15


The bullet's speed is $336m/s$

Work Step by Step

The angular displacement between 2 bullet holes is $\Delta\theta=0.24rad$ and the angular speed is $\overline\omega=95rad/s$ $$\Delta t=\frac{\Delta\theta}{\overline\omega}=2.53\times10^{-3}s$$ $\Delta t$ is the amount of time it takes the bullet to fly from the left disk to the right one. Since the distance between them is $d=0.85m$, the bullet's speed is $$v=\frac{d}{\Delta t}=336m/s$$
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