## Physics (10th Edition)

Published by Wiley

# Chapter 8 - Rotational Kinematics - Problems - Page 212: 8

#### Answer

The distance traveled by the jet is $162.7m$

#### Work Step by Step

We have the angle the moon subtends $\theta=9.04\times10^{-3}rad$ and the distance from the tower to the jet $r=18km$ As we can see from the figure below, the distance traveled by the jet is the arc length of the circle with radius $r$, where the angle of the arc is $\theta$. Therefore, $$s_{jet}=r\theta=162.7\times10^{-3}km=162.7m$$

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