Answer
The angular displacement of the baseball is $20.76rad$
Work Step by Step
We have $\Delta t=0.6s$ and $\overline\omega=330rev/min$
1 revolution equals $2\pi$ radians and 1 minute equals 60 seconds
So, $\overline\omega=\frac{330\times2\pi}{60}=34.6rad/s$
The angular displacement of the baseball is $$\Delta \theta=\overline\omega\Delta t=20.76rad$$
