Answer
$F=102.5N$
Work Step by Step
We have $$\overline P = \frac{W}{t}=\frac{(F\cos\theta)s}{t}$$ $$F=\frac{\overline Pt}{s\cos\theta}$$
$\overline P=82W$, $t=1.5s$ and $s=1.2m$. The pulling force applied goes the same way as the bar's motion, so $\cos\theta=\cos0=1$
$$F=102.5N$$
