Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Check Your Understanding - Page 154: 9

Answer

a) is correct.

Work Step by Step

The change in the astronaut's potential energy is $$\Delta PE=PE_f-PE_0=mg(h_f-h_0)$$ We know the gravitational acceleration on earth is greater than that on the moon: $g_{earth}\gt g_{moon}$, which means on earth, the gravitational potential energy $PE$ changes by a greater amount.
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