Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Check Your Understanding - Page 152: 8


c) is correct.

Work Step by Step

The work-energy theorem states that $$W=KE_f-KE_0=\frac{1}{2}m(v_f^2-v_0^2)$$ $W$ is the work done by a net external force on the object As the theorem indicates, a net external force acting on the particle means there is a change in both the particle's kinetic energy and velocity. Therefore, c) is correct.
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