Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 140: 48


Every second, the cylinder should make $0.85$ revolutions.

Work Step by Step

The clothes will lose contact with the wall when there is no normal force exerted on the clothes by the wall. In other words, the clothes' weight provides all the centripetal force: $F_c=W$ In the figure below, we see that the component of the weight that provides $F_c$ at the angle given is $mg\cos20$. Therefore, $$mg\cos20=F_c=\frac{mv^2}{r}$$ $$g\cos20=\frac{v^2}{r}$$ $$v=\sqrt{rg\cos20}$$ We have $r=0.32m$ and $g=9.8m/s^2$. So $$v=1.717m/s$$ Now we find the period $T$: $$T=\frac{2\pi r}{v}=1.17s$$ So the cylinder should finish $1 rev$ every $1.17s$, meaning every second, the cylinder should make $1/1.17=0.85$ revolutions.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.