Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 140: 45


At 6 o'clock position, $T=17.96N$ At 12 o'clock position, $T=14.04N$

Work Step by Step

The stick tension is in fact the normal force acted on the ball: $T=F_N$ At 3'o clock position, only the tension provides the centripetal force: $F_c=T=16N$ At 6'o clock position, the tension opposes the ball's weight, therefore, $$F_c=T-mg$$ $$T=F_c+mg=16+0.2\times9.8=17.96N$$ At 12'o clock position, the tension support the ball's weight to provide for $F_c$, therefore, $$F_c=T+mg$$ $$T=F_c-mg=16-0.2\times9.8=14.04N$$
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