Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 118: 92

Answer

(a) $a=g\tan\theta$ (b) $a=1.73m/s^2$ (c) $\theta=0^o$

Work Step by Step

(a) As the van accelerates with acceleration $a$ forward, the sphere swings backward with similar acceleration $a$. On horizontal side, if we call the force that pushes the sphere backward $F$, we have $$F=m_{sphere}a$$ Similarly, on vertical side, the sphere is under its weight: $$W=m_{sphere}g$$ Angle $\theta$ can be found by taking the tangent of the horizontal over the vertical: $$\tan\theta=\frac{F}{W}=\frac{a}{g}$$ $$a=g\tan\theta$$ (b) When $\theta=10^o$, $a=g\tan10=1.73m/s^2$ (c) If the van moves with constant velocity, its acceleration $a=0$, which means $$g\tan\theta=0$$ $$\tan\theta=0$$ $$\theta=0^o$$
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