Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 117: 82

Answer

$a=0.14m/s^2$

Work Step by Step

The man's upward movement is influenced by 3 forces: - The tension in the half rope in the man's hands $T_1$ and the tension in the other half tied to his waist $T_2$. Both forces pull the man upward and result from the pulling by his hands, so $T_1=T_2=358N$ - The man's weight $mg$, which points downward According to Newton's 2nd Law, we have $$\sum F=T_1+T_2-mg = ma$$ $$(2\times358N)-(72kg\times9.8m/s^2)=(72kg)a$$ $$(72kg)a=10.4N$$ $$a=0.14m/s^2$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.