## Physics (10th Edition)

Published by Wiley

# Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 116: 57

68 kg

#### Work Step by Step

$mg\sin\theta=f_{s}$ $\implies m=\frac{f_{s}}{g\sin\theta}=\frac{390\,N}{9.8\,m/s^{2}\times\sin 36^{\circ}}=68\,kg$

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