#### Answer

68 kg

#### Work Step by Step

$mg\sin\theta=f_{s}$
$\implies m=\frac{f_{s}}{g\sin\theta}=\frac{390\,N}{9.8\,m/s^{2}\times\sin 36^{\circ}}=68\,kg$

Published by
Wiley

ISBN 10:
1118486897

ISBN 13:
978-1-11848-689-4

68 kg

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