Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 31 - Nuclear Physics and Radioactivity - Problems - Page 899: 4

Answer

In order to double the nuclear radius number of nucleons has to be increased by a factor of $1.2599$

Work Step by Step

Nuclear radius is given by $r=(1.2\times10^{-15}m)A^{\frac{1}{3}}$.........(1) here $A$ is number of nucleon number of the nucleus. I want Radius to be double so new radius $r_{double}=2r$ ........(2) and in double nucleus radius suppose number of nucleon is $A_{new}$ so $r_{double}=(1.2\times10^{-15}m)A_{new}^{\frac{1}{3}}$.....(3) from equation (1) and (3) putting the value in equation (2) will give us $(1.2\times10^{-15}m)A_{new}^{\frac{1}{3}}=2\times(1.2\times10^{-15}m)A^{\frac{1}{3}}$ $A_{new}^{\frac{1}{3}}=2A^{\frac{1}{3}}$ $A_{new}=(2)^{\frac{1}{3}}A$ $A_{new}=1.2599A$ so in order to double the nuclear radius number of nucleons has to be increased by a factor of $1.2599$
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