Answer
$4.1\times10^{-15}m$
Work Step by Step
Mass number A= 18+22= 40.
Radius of the nucleus= $1.2\times10^{-15}m\times A^{\frac{1}{3}}$
Thus, we find:
= $1.2\times10^{-15}m\times 40^{\frac{1}{3}}= 4.1\times10^{-15}\,m$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 31 - Nuclear Physics and Radioactivity - Problems - Page 899: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
