Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 31 - Nuclear Physics and Radioactivity - Problems - Page 899: 2



Work Step by Step

Mass number A= 18+22= 40. Radius of the nucleus= $1.2\times10^{-15}m\times A^{\frac{1}{3}}$ Thus, we find: = $1.2\times10^{-15}m\times 40^{\frac{1}{3}}= 4.1\times10^{-15}\,m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.