Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 29 - Particles and Waves - Problems - Page 840: 3


6.3 eV

Work Step by Step

Frequency, ν= $3.00×10^{15}$Hz Planck's constant, h=$ 6.626×10^{-34}$Js Maximum kinetic energy, $K_{max}$= 6.1 eV We know that $K_{max}$= $hν- Φ_{0}$, where $Φ_{0}$ is the work function of the metal. Thus, we find: $Φ_{0}$=hν-$K_{max}$ = $( 6.626×10^{-34}Js×3.00×10^{15}s^{-1}$)- 6.1 eV =($1.99×10^{-18}J$)- 6.1 eV = ($1.99×10^{-18}J×\frac{6.242×10^{18}eV}{1J}$)- 6.1 eV = 12.4 eV- 6.1 eV = 6.3 eV
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