Answer
6.3 eV
Work Step by Step
Frequency, ν= $3.00×10^{15}$Hz
Planck's constant, h=$ 6.626×10^{-34}$Js
Maximum kinetic energy, $K_{max}$= 6.1 eV
We know that $K_{max}$= $hν- Φ_{0}$, where $Φ_{0}$ is the work function of the metal.
Thus, we find:
$Φ_{0}$=hν-$K_{max}$
= $( 6.626×10^{-34}Js×3.00×10^{15}s^{-1}$)- 6.1 eV
=($1.99×10^{-18}J$)- 6.1 eV
= ($1.99×10^{-18}J×\frac{6.242×10^{18}eV}{1J}$)- 6.1 eV
= 12.4 eV- 6.1 eV = 6.3 eV
