## Physics (10th Edition)

Frequency, ν= $3.00×10^{15}$Hz Planck's constant, h=$6.626×10^{-34}$Js Maximum kinetic energy, $K_{max}$= 6.1 eV We know that $K_{max}$= $hν- Φ_{0}$, where $Φ_{0}$ is the work function of the metal. Thus, we find: $Φ_{0}$=hν-$K_{max}$ = $( 6.626×10^{-34}Js×3.00×10^{15}s^{-1}$)- 6.1 eV =($1.99×10^{-18}J$)- 6.1 eV = ($1.99×10^{-18}J×\frac{6.242×10^{18}eV}{1J}$)- 6.1 eV = 12.4 eV- 6.1 eV = 6.3 eV