Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 29 - Particles and Waves - Problems - Page 840: 1

Answer

(a)$\lambda=163.03nm$ (b)$f=1.84\times10^{15}Hz$ (c) ultraviolet rays

Work Step by Step

Given that dissociation energy of cynogen molecule is $E=1.22\times10^{-18}J$ suppose energy is provided by single photon . frequency of photon $f$ and wavelength of photon is $\lambda$ From Plank's hypothesis $E=hf=\frac{hc}{\lambda}$ , here $c$ is speed of light (a) wavelength calculatio $E=\frac{hc}{\lambda}$ $\lambda=\frac{hc}{E}$ putting $h=6.63\times10^{-34}J.s$, $E=1.22\times10^{-18}J$, $c=3\times10^{8}m/s$ $\lambda=\frac{6.63\times10^{-34}J.s\times3\times10^{8}m/s}{1.22\times10^{-18}J} =16.303\times10^{-8}m=163.03\times10^{-9}m$ $\lambda=163.03nm$ (b) frequency $E=hf$ $f=\frac{E}{h}$ putting $h=6.63\times10^{-34}J.s$, $E=1.22\times10^{-18}J$ $f=\frac{1.22\times10^{-18}J}{6.63\times10^{-34}J.s}=0.18401\times10^{16}/s$ $f=1.84\times10^{15}Hz$ (C) as its frquency is close to $10^{16}Hz$ it lies in the range of ultraviolet rays.
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