## Physics (10th Edition)

Refractive index: n= $\frac{c}{v}= \frac{2.998\times10^{8}m/s}{2.201\times10^{8}m/s}$ = 1.362 We can see that the refractive index of ethyl alcohol is 1.362 from Table 26.1. Hence, the given substance with n= 1.362 can be ethyl alcohol.