Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems: 54

Answer

22 m

Work Step by Step

Let down be the negative direction $v^{2}=u^{2}+2ax$ $u=±\sqrt{ ((-27)^{2}-2(-9.8)(-15))}$ $u=-\sqrt{ (435)}$ since the gun was fired downwards To find maximum height above the cliff edge: $v^{2}=u^{2}+2ax$ $x=\frac{(0)^{2}-435}{2(-9.8)}\approx22 $ m
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.