Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 50: 54


22 m

Work Step by Step

Let down be the negative direction $v^{2}=u^{2}+2ax$ $u=±\sqrt{ ((-27)^{2}-2(-9.8)(-15))}$ $u=-\sqrt{ (435)}$ since the gun was fired downwards To find maximum height above the cliff edge: $v^{2}=u^{2}+2ax$ $x=\frac{(0)^{2}-435}{2(-9.8)}\approx22 $ m
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