## Physics (10th Edition)

1.5 $m/s^{2}$ down
Let down be the negative direction $v=u+at$ $a=\frac{v-u}{t}$ $a=\frac{(-15)-(15)}{(20.0)}=-1.5\; m/s^{2}$ Hence, the acceleration is 1.5 $m/s^{2}$ down