Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems: 48

Answer

1.5 $m/s^{2}$ down

Work Step by Step

Let down be the negative direction $v=u+at$ $a=\frac{v-u}{t}$ $a=\frac{(-15)-(15)}{(20.0)}=-1.5\; m/s^{2}$ Hence, the acceleration is 1.5 $m/s^{2}$ down
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.