Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 50: 48


1.5 $m/s^{2}$ down

Work Step by Step

Let down be the negative direction $v=u+at$ $a=\frac{v-u}{t}$ $a=\frac{(-15)-(15)}{(20.0)}=-1.5\; m/s^{2}$ Hence, the acceleration is 1.5 $m/s^{2}$ down
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