Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Focus On Concepts - Page 47: 6

Answer

The correct option is (c) $10\ \rm km/h^2$ due east

Work Step by Step

We know that acceleration is the rate of change of velocity, i.e. $a=\dfrac{v-u}{t}$ Where $v$ is the final velocity, $u$ is the initial velocity, and $t$ is the time. $a=\dfrac{65\ \rm km/h-80\ \rm km/h}{1.5\ \rm h}$ $a=-10\ \rm km/h^2$ The negative sign implies that the train is slowing down, hence we can say that the acceleration of the train is $10\ \rm km/h^2$ due east.
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