Answer
The correct option is (d).
$a_{silver Bullet}=1.2a_{shotgun}$
Work Step by Step
Since both Silver Bullet and Shotgun starts from rest, their initial velocity will be zero, i.e.
$u=0$
Also, it is given that, Silver Bullet runs $1.2$ times farther than Shotgun for the same given time, i.e.
$s_{sb}=1.2s_{s}\quad\quad....1$
Let us now apply the second equation of motion for Silver Bullet,
$s_{sb}=ut+\dfrac{1}{2}a_{sb}t^2=0+\dfrac{1}{2}a_{sb}t^2=\dfrac{1}{2}a_{sb}t^2$
Again using the second equation of motion for Shotgun,
$s_{s}=ut+\dfrac{1}{2}a_st^2=\dfrac{1}{2}a_st^2$
Let us substitute the values of $s_{sb}$ and $s_s$ in equation 1, we get
$\dfrac{1}{2}a_{sb}t^2=1.2\times\dfrac{1}{2}a_st^2$
Hence we get,
$a_{sb}=1.2a_s$
or, $a_{SilverBullet}=1.2a_{Shotgun}$
