Answer
$1.1\times10^{3}$ V
Work Step by Step
Recall: U= $\frac{1}{2}CV^{2}$.
Rearranging the equation, we get:
V= $\sqrt {\frac{2U}{C}}$
Plugging in the values, we have:
Potential difference: V= $\sqrt {\frac{2\times73J}{120\times10^{-6}F}}= 1.1\times10^{3}V$
