Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 19 - Electric Potential Energy and the Electric Potential - Problems - Page 539: 42

Answer

2.9 $\mu F$

Work Step by Step

Charge, q= 4.3 $\mu C$ Voltage, V= 1.5 V Thus, we find: Capacitance, C= q/V = $\frac{4.3\times10^{-6}C}{1.5V}\approx 2.9 \mu F$
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