Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 14 - The Ideal Gas Law and Kinetic Theory - Problems - Page 387: 62

Answer

49.87 s

Work Step by Step

Here we use equation 14.7 $U=\frac{3}{2}nRT$ to find the time. We can write, $$time\space (t)=\frac{Energy}{Power}=\frac{U}{Power}=\frac{\frac{3}{2}nRT}{Power}$$ Substituting $PV=nRT$ from the ideal gas law into the above equation yields, $t=\frac{3PV}{2Power}$; Let's plug known values into this equation. $t=\frac{3(6.2\times10^{5}Pa)(0.01\space m^{3})}{2(0.25\space hp)(\frac{746\space W}{1\space hp})}=49.87\space s$
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