Answer
(b) The cube
Work Step by Step
We have
$\Delta V = \beta V_0 \Delta T$
Here $\beta$ and $\Delta T$ are same for both cube and sphere but $V_0$ is different for both.
Since $V_0$ of cube is greater than $V_0$ of sphere $\Delta V$ of cube will be greater than $\Delta V$ of sphere.
